logs sometimes float vertically in a lake because one end has become water-logged and denser than the other. what is the average density (in kg/m3) of a uniform-diameter log that floats with 47.0% of its length above water?

Respuesta :

The typical den The log has an average density of 530 kg/m³, which is measured in kilograms per cubic meter.

How do you determine the typical density?

By multiplying each compound's density by its volume and then dividing the result by the sum of all the volumes, one can determine the mixture's average density.

Knowing that;

A uniformly sized log floats with 47.0% of its length above the surface.

from the formula for the Archimedes principle;

Average object density / fluid density equals the coefficient of friction.

We are aware that water has a density of 1000 kg/m³.

47.0% of the log's length is now above water, making it float now.

Submerged fraction is therefore 100% - 47% = 53% = 0.53.

from our formula;

friction submerged = average object density / fluid density

We swap out

0.53 = Average Object Density / 1000 kg/m³

The object's average density is 0.53 1000.

The object's average density is 530 kg/m³.

Consequently, the log's average density (in kg/m3) is 530 kg/m³.

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