contestada

a rocket accelerates from rest at 28 m/s2 for 9.6 s. how far will it cover during this time? answer in units of m.

Respuesta :

The distance covered would be 821.4 m You can use the following conventional formula to get the distance traveled at constant acceleration over a specific period of time: d = 1/2 * a * t²

0 m/s is the initial velocity, or u.

m/s is the final velocity.

t = 7.4 seconds of time.

30 m/s2 is the acceleration, a.

displacement plus s =? m

There is no kinematic equation that can calculate the displacement using the variables provided in the question, hence the solution must be two steps.

Use the kinematic equation below to get the rocket's final velocity.

v = u + at

v=0 + (30 m/s2 7.4 s) = 222 m/s

Use the kinematic equation below to determine the rocket's displacement.

s = ½(v + u)t

s = 0.5 (7.4 s) = 821.4 m (222 m/s + 0 m/s)

Learn more about displacement here-

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