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There are 51 houses on a street. Each house has an address between 1000 and 1099, inclusive. Show that at least two houses must have addresses that are consecutive integers. In particular, identify the set of pigeons and the set of holes.

Respuesta :

Established that at least two houses have addresses that reflect consecutive numbers. houses; Every house consists of an address between 1000 and 1099.

What is the principle of the pigeon hole?

There are 51 homes and 100 possible addresses. There must be at least one address between each house in order for there to be no houses with consecutive addresses. To do this, only give houses even numbers (leaving odd addresses as the buffer address)

Giving houses even numbers (leaving odd addresses as the buffer address) Right now, we

According to the pigeon hole principle, if items are put into boxes, at least one box must contain at least?

As a result, it is impossible to assign distinct addresses to several houses without using at least one consecutive integer. As a result, there must be at least one instance of a home with consecutive integers, which implies that there are at least two houses.

To know more about pigeon hole visit:-

https://brainly.com/question/29591539

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