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What is the output for this code below class XXX: x, y=1,2; def fun(self, a,b): return self.x+self.y class yyy: x, y=3,4 def fun(self, a,b): return a+b class zzz: x, y=5,6 def fun(self, a,b): return self.x + self.y obx=xxx() oby=xxx.yyy(). obz=xxx.yyy.zzz(); print(obx. fun(1,2)+oby. fun(0,0)+obz. fun(1,1))

Respuesta :

The output for that code is 14.

How to calculate output?

The code is use fun as a function in python. In the code there are three functions which is fun in class xxx, fun in class yyy, and fun in class zzz.

For class xxx, the output is always same no matter the argument that been used, the output is x+y = 1+2 = 3.

For class yyy, the output is depend on argument, the output is a+b = 0+0 = 0.

For class zzz, the output is always same no matter the argument that been used, the output is x+y = 5+6 = 11.

Next, in print we total all result from each fun. So, 3+0+11 is 14.

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