Theoretical centre-to-centre distance (C)=3.25 which is the distance between the centers of the pinion and gear
Given data:
No. of teeth on the pinion(TP)=17.
Diametral pitch(pd)=8 teeth/in.
The rotational speed of the pinion(NP)=1120 rev/min or 1120 rpm.
The rotational speed of the gear(NG)=544 rev/min or 544 rpm.
To calculate:
No. of teeth on gear(TG) & theoretical centre-to-centre distance(C).
We know that;
Diametral pitch(pd)=No. of teeth in the gear/Diameter of the gear
For pinion,
pd=TP/DP
Pittiong the values in above eq.
8 teeth/in =17/DP =>DP=17/8 in.
or DP=2.125 in.
Gear ratio(G)=(NP/NG)=(TG/TP)=(DG/DP)
(NP/NG)=(TG/TP)
1120/544 =TG/17 =>TG=35
therefore No. of teeth the gear(TG)=35 {Ans}
Also from gear ratio formula,
(NP/NG)=(DG/DP)
1120/544=DG/2.125
DG=4.375 in.
In figure I have drawn a rough diagram of the pinion and gear arrangement which will help you to understand how to calculate the centre-to-centre distance(C)
From fig.,
centre to centre distance,C=rP+rG {Where rP and rG are the radii of pinion and gear respectively}
C=(DP+DG)/2 {\large \because Diameter =2*radius}
C=(2.125+4.375)/2 in. =3.25 in.
therefore Theoretical centre to centre distance (C)=3.25
To learn more about centre to centre distance
https://brainly.com/question/11878555
#SPJ4
