Respuesta :
The force exerted by each of the 10 braces is 2.0534 x 10⁴ N.
The force is defined as the shear stress or pressure applied per unit area.
- Mathematically, F = P/A
- SI unit of force is Newton (N).
The wall is 17.0-m-high and 11.0-m-long
Its bracing is under construction
The force is exerted by each of the 10 braces, if a strong wind exerts a horizontal force of 630 N on each square meter of the wall.
Let the net force from the wind acts at a height halfway up the wall and that all braces exert equal forces parallel to their lengths.
Considering the pivot at the base of wall.
From the equilibrium of forces, we have
r₁ * Fwind = r₁ * Fbsinθ
By substituting the values,
Fb = Fwind /10sin35°.............(1)
The wind force is also given by
Fwind = Horizontal force or pressure * Area
Fwind = F/A * hw
Fwind = 630 x 17 x 11
F wind = 117810 N
From equation (1), we have
Fb = Fwind /10sin35°
Fb = 117810 /10sin35°
Fb = 20539.54 N
0r Fb = 2.0534 x 10⁴ N
Thus, the force exerted on each of the 10 braces is 2.0534 x 10⁴ N.
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