The given trigonometric equations have the value tan x, -cot x.
Since the given trigonometric equations are: cos2x-cos4x/sin2x+sin4x and cos2x+cos4x/sin2x-sin4x. The problem is related to trigonometric Ratios, which are the ratios of the side of a right-angled triangle.Now for the equation (cos 2x - cos 4x )/(sin2x +sin4x)
since we know the formulas :
cos A + cos B = - sin (A+B)/2 sin(A-B)/2
sin A - sin B = sin( A+B)/2 cos (A-B)/2
so for the equation, we can
= (-sin 3x) sin ( -2x)/2)/( cos 3x cos x)
= sin 3x sin x/ (sin 3x) cos x
= tan x
for the second equation cos2x+cos4x/sin2x-sin4x
= cos 3x cosx/ cos3x sin(- x)
= - cot x
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