what is the oxidation state of each element in the compound pbso4? refer to the rules for oxidation states and this list of common polyatomic ions. select the correct answer from each drop-down menu. the oxidation state of lead is . the oxidation state of sulfur is . the oxidation state of oxygen is .

Respuesta :

The oxidation state of each element in the compound PbSO₄ : the oxidation state of lead is +2 . the oxidation state of sulfur is + 6 . the oxidation state of oxygen is -2.

The oxidation states is total number of the electrons the an atom will be losses or gain to make a chemical bond with the other atom. the oxidation state is the charge represent the ions. for the neutral compound the total charge is zero. the charge in the oxygen is - 2 and the charge on the lead is + 2 , now we have to calculate the charge of the sulfur :

oxidation state of sulfur = PbSO₄

                                        => + 2 + x + 4(-2) = 0

                                        => x + -6 = 0

                                        => x = +6

oxidation state of sulfur = + 6

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