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a 0.850 kg block is attached to a spring with spring constant 18.0 n/m. while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 38.0 cm/s.

Respuesta :

Amplitude=0.08257cm

Given mass=0.850kg

k=18.0 n/m

velocity=38cm/s

Conservation of energy?

we know here conservation of energy

maximum kinetic energy = maximum potential energy

[tex]1/2 m v^{2}[/tex] =[tex]1/2 k A^{2}[/tex]

here we know k is spring constant and m is mass and A is amplitude and v is velocity.

So to find value for A solve

[tex]A=\sqrt{m v^{2} /k}[/tex]

By plugging in values given in the question we get

[tex]A=\sqrt{0.850 (0.38^{2})/18 }[/tex]

[tex]A=0.08257[/tex]cm

Spring mass problem

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