The two objects have the same mass m, and the same size radius r, the moments of inertia about an axis going through the center of each object are [tex]\frac{1}{2} MR^{2}[/tex] and [tex]\frac{2}{5} MR^{2}[/tex] .
We will calculate the moment of inertia of a solid sphere by integrating multiple inertias of the disc.
I = 1/2MR²
[tex]dI = \frac{1}{2} dMR^{2}[/tex]
[tex]dM =[/tex] ρ [tex]dV[/tex]
V = 4/3 πR³
[tex]dV[/tex] = πR²dx
[tex]dM =[/tex] ⍴πR²dx
Putting [tex]dM[/tex] in dI
dI =1/2⍴πR4dx
y² = R² – r²
dI = 1/2⍴π(R² – r²)2dx
Integrating both sides, from 0 to R
I = 8/15⍴πR5
Replacing ⍴ = M/V
⍴ = M/4/3 πR³
Substituting ⍴ in I,
Final Formula: – I = 2/5MR²
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