At 2:00 p.m., Louisa leaves Kansas City in her car traveling east on I-70 toward St. Louis at an average speed of 68 mph. At precisely the same time, Antonio leaves St. Louis in his car traveling west on I-70 toward Kansas City at an average speed of 57 mph. The driving distance from St. Louis to Kansas City is 240 miles. At what time, to the nearest minute, will they drive past each other on I-70 ? A. 3:46 p.m. B. 3:50 p.m. C. 3:53 p.m. D. 3:55 p.m. E. 4:06 p.m.

In this question, we are given that Louisa starts from Kansas city travels to the east at the rate of 68 miles per hour, and Antonio starts from St. Louis and travels west at the rate of 57 miles per hour.

So here both of these people are traveling towards each other, and the distance between Kansas City and St. Louis is 240 miles.

Both of them begin at the same time, i.e., at 2 p m.

We need to find the time t at which both of them go past each other.

First find out the distance covered by person a in time t.

We know that speed = distance / time.

distance = speed * time

In this case, Louisa would have covered a distance of 68 t in time t and Antonio would have covered a distance of 57t in time t.

Since both of them are traveling towards each other, we must add up the distance that has traveled and this distance that has been traveled must be equal to 240 miles when both of them are passing each other,

So, we get an equation

68t + 57t = 125

t = 1.92

t = 1 hour and 55 minutes

Since both of them began at 2, p m. If we add 1 hour and 55 minutes to this, then it means that they would meet each other at 3:55 p. m.

Therefore, they would meet each other at 3:55 p. m.

Learn more about an equation here:

https://brainly.com/question/649785

#SPJ4