The probability of drawing a green ball at random is the fraction 1/6
The probability of an event occurring is the fraction of the number of required outcome divided by the total number of possible outcomes.
From the question, we have 2 green, 7 yellow, and 3 purple balls in the box which gives us the total number of balls to be 12
our required outcome is concerned with green balls that are just 2
thus,
probability of drawing a green ball = 2/12
probability of drawing a green ball = 1/6
Therefore, by proper application of probability the fraction 1/6 is the probability of getting a green ball at random.
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