Respuesta :
When x^3+x^2+2x+2 is divided by (x+1) then remainder is 2.
In the given question, we have to find what is remainder when x^3+x^2+2x+2 is divided by (x+1).
To find the remainder there are two ways. First we divide the x^3+x^2+2x+2 by (x+1). Second we find the value of from (x+1) by equating (x+1) equal to zero. The put the value of x in the expression x^3+x^2+2x+2.
In this we ca easily find the remainder.
Now we firstly find the value of x;
(x+1) = 0
Subtract 1 on both side we get;
x= −1
Now put x=-1 in the expression x^3+x^2+2x+2.
x^3+x^2+2x+2 = (−1)^3+(−1)^2+2(−1)+2
x^3+x^2+2x+2 = −1+1−2+2
x^3+x^2+2x+2 = 0
Hence, when x^3+x^2+2x+2 is divided by (x+1) then remainder is 0.
To learn more about division of polynomial link is here
brainly.com/question/17167810
#SPJ4
The right question is:
What is remainder when x^3+3x^2+3x+1 is divided by (x+1)?
