When x^2−x+1 is divided by (x+1) then remainder is 1.
In the given question, we have to find what is remainder when x^2−x+1 is divided by (x+1).
To find the remainder there are two ways. First we divide the x^2−x+1 by (x+1). Second we find the value of from (x+1) by equating (x+1) equal to zero. The put the value of x in the expression x^2−x+1.
In this we ca easily find the remainder.
Now we firstly find the value of x;
(x+1) = 0
Subtract 1 on both side we get;
x= −1
Now put x=−1 in the expression x^2−x+1.
x^2−x+1 = (−1)^2−(−1)+1
x^2−x+1 = 1−1+1
x^2−x+1 = 1
Hence, when x^2−x+1 is divided by (x+1) then remainder is 1.
To learn more about division of polynomial link is here
brainly.com/question/12978781
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The right question is:
What is remainder when x^2−x+1 is divided by (x+1)?
