The solution of the system of equations y = -3x - 2 and 5x + 2y = 15 is (-19, 55)
The first equation is
y = -3x - 2
The second equation is
5x + 2y = 15
To solve this problem we have to use the substitution method
Substitute the value of y = -3x - 2 in the second equation 5x + 2y = 15
5x + 2(-3x -2) = 15
5x - 6x - 4 = 15
-x - 4 = 15
-x = 15 + 4
-x = 19
x = -19
Substitute the value of x in the first equation
y = -3x - 2
y = -3(-19) - 2
= 57 - 2
= 55
Therefore, the solution of the system of equation is (-19, 55)
I have solved the question in general, as the given question is incomplete
The complete question is
What is the solution to the system of equations
y = -3x - 2 and 5x + 2y = 15
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