The value of a₀ is 5 and value of k is 12 if the exponential model of 5 ˣ 12x is written with the base e.
Exponential models portray circumstances where the pace of progress of something is straightforwardly corresponding to the amount of that thing there is. In number related terms: dy dt = ky where dy dt is the pace of progress in a moment, y is how much what we're discussing right then and there, and k is the consistent of proportionality. We need to use logarithmic functions to evaluate the values.
We are given function in form of x which is f(x) = 5×12ˣ,it is equivalent to
=>f(x)=5 × expo(ln(12ˣ)
=>f(x) =5 ˣ [tex]e(^1^2)^x[/tex]
On comparing with the given equation - a₀[tex]e^(k)^x[/tex] ,we get
=>a₀=5 and k=12.
Hence, required values are 5 and 12,
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