A weight is attached to the other end of the pulley and released, resulting in 3-kg mass to rise 50 cm in 1.0 s. The mass of the weight is 3.68 kg
The problem can be solved using the equation of motion:
s = u . t + 1/2 a . t²
Where:
s = distance
u = initial velocity
t = time period
a = acceleration
Substitute the given parameters:
s = 50 cm = 0.5 m
u = 0
t = 1
Hence,
0.5 = 0 + 1/2 a . 1²
1/2 a = 0.5
a = 1 m/s²
After obtaining the acceleration, a, use the Newton's 2nd law of motion.
Forces acting on mass 3 kg : tension (T), weight (mg).
Hence,
T - mg = ma
T = m (g + a)
Let M = mass of the weight.
Forces acting on M : tension (T), weight (Mg). Hence,
Mg - T = Ma
T = M (g - a) (substitute T = m (g + a) )
m (g + a) = M (g - a)
M = m x (g + a) / (g - a)
= 3 x (9.8 + 1) / (9.8 - 1)
= 3.68
Hence, the mass of the weight is 3.68 kg
Learn more about Newton's law here:
https://brainly.com/question/24994188
#SPJ4
