30.05 KW power must the pump supply to the system to pump oil from the lower reservoir to the upper reservoir at a rate of 0.3 m3/s.
P1/Pg + a1V12/2g + z1 + hp = P2/ Pg + a2 v22/2g + z2 + ∑h2
hp = 12 + [tex]v ^{2}[/tex]/2g [ 0.03 + fL/D +1 ]
Calculate the velocity
When an object is moving, its velocity serves as a measure of how quickly its location is changing as it is seen from a given point of view and as time is measured using a specific unit of measurement.
V= Q/A
= Q/ [tex]\pi[/tex] [tex]D^{2}[/tex]/4
= 0.2 / [tex]\pi[/tex] [tex][30]^{2}[/tex]
= 2.83 ms/s
P = pgQ[tex]h_{p}[/tex]
P= ( 940kg/m3) (9.81 m/s2) (0.20 m3/s) (16.2m)
P= 300054.8 W (1Kw/ 1000W) = 30.05 kW
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