The flow rate of water moving at a speed of 1.95 m/s through a hose with an internal diameter of 1.6 cm is 0.39 L / s
Q = A v
Q = Flow rate
A = Area
v = Velocity
Since the outlet of water is through a hose,
A = π r²
A = π d² / 4
d = 1.6 cm = 0.016 m
A = ( 3.14 * 0.016² ) / 4
A = 0.0002 m²
The velocity of water is 1.95 m / s
Q = 1.95 * 0.0002
Q = 0.00039 m³ / s
Q = 0.00039 * 1000 L / s
Q = 0.39 L / s
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