if each of 20 people generated a random sample of shole numbers and constructed a 95% confidence interval for the proportion that are odd, how many intervlas are expected to contain the true proportion

Respuesta :

The control limits that include 95% of the sample means be,

(19.9671 , 20.0329).

Given, each of 20 people generated a random sample of whole numbers and constructed a 95% confidence interval for the proportion that are odd.

we have to find the confidence interval under confidence of 95%.

Subtract 1 from your sample size. 25 – 1 = 24. This gives you degrees of freedom.

Subtract the confidence level from 1, then divide by two.

(1 – 0.95) / 2 = 0.05

For 24 degrees of freedom (df) and α = 0.05, the result is 1.645.

Divide your sample standard deviation by the square root of your sample size.

0.1 / √(20) = 0.02

Now, 0.02 × 1.645 = 0.0329

The lower end of the range

20 – 0.0329 = 19.9671

The upper end of the range

20 + 0.0329 = 20.0329

Hence, the confidence interval be, (19.9671 , 20.0329)

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