14.08 meter per second fast a(n) 80 kg man need to run in order to have the same kinetic energy as an 8.0 g bullet fired at 380 m/s
We have specified that a man weighs 80 kilograms. Additionally, a bullet's mass is equivalent to 8 grams, which is equal to 8 times 10 to the minus 3 kilogram, and its velocity is equal to 380 meters per second. We will now determine the velocity of a man. Now that we have established that the kinetic energy of the guy is equal to the kinetic energy of the bullet, we can conclude that both are equal. In other words, we may write this as 1 divided by 2 capital m multiplied by v square capital m = 1 divided by 2 capital b multiplied by v square capital b.
Generally the equation for the kinetic energy is mathematically given as
K.E= 1/2*m*[tex]v{2}[/tex]
Therefore
K.E =1/2 *0.008*[tex](420){2}[/tex]
K.E=672.4j
Therefore
[tex]v2[/tex]=673.4*2/85
[tex]v2[/tex]=15.821
v=4.0m/s
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