The potential of this cell is +0.0385.
Zn | Zn2+(0.050 M) || Zn2+(1.00 M) | Zn
Zn(s) ==> Zn2+(0.050 M) (oxidation on the left side)
Zn2+(1.00M) + 2e- ==> Zn(s) (reduction on the right side)
Zn2+(1.00M) ==> Zn2+(0.050M)
Ecell = Eºcell - RT ln Q and assuming this situation is at 25ºC (298K), we have...
Ecell = Eºcell - 0.0592 / 2 log Q
Q = 0.050 / 1.00 = 0.05
Ecell = 0 - 0.0296 * log 0.05
Ecell = -0.0296 * -1.301
Ecell = +0.0385 (note the potential is positive, meaning the reaction is spontaneous)
Also note that this is the INSTANTANEOUS cell potential. As time goes on, the cell potential will become ZERO.
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