question 31 pts for the data given below, we construct a 90% confidence interval for the population mean. 42.3 59.2 45.4 55.8 49.0 39.7 56.2 54.6 45.8 60.6 55.7 46.1 58.3 44.4 find the upper bound (round off to first decimal place)

Respuesta :

the upper bound is 54.2.

What is confidence interval?

A confidence interval (CI) for an unknown parameter in frequentist statistics is a range of estimations. The most popular confidence level is 95%, but other levels, such 90% or 99%, are occasionally used for computing confidence intervals. The fraction of related CIs over the long run that actually contain the parameter's true value is what is meant by the confidence level. The degree of confidence, sample size, and sample variability are all factors that might affect the width of the CI. A larger sample would result in a narrower confidence interval if all other factors remained constant. A wider confidence interval would also be required by a higher confidence level and would be produced by a sample with more variability.

31 pts for the data given below, we construct a 90% confidence interval for the population mean.

42.3 59.2 45.4 55.8 49.0 39.7 56.2 54.6 45.8 60.6 55.7 46.1 58.3 44.4 .

MEAN = 50.94

varience = 48.55

s.d = √48.55 = 6.96.

C=0.90,α= 1-0.90=0.10

t=ta/2.df = 1.771 (using t value table)

90% confidence interval

(47.6378,54.2336)

Hence the upper bound is 54.2.

Learn more about confidence intervals, by the following link.

https://brainly.com/question/17097944

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