The difference for the nth maxima is 500n farther is it from the dot on the screen in the center of fringe e to the left slit than it is from the dot to the right slit
The maximum intensity occurs at this location in a single-slit diffraction pattern as a result of secondary waves reinforcing one another there.
Distance from the screen's center dot
The difference is (500)(0) = 0 when viewed from the center (zeroth) fringe.
The difference for the first maximum is 500 nm.
It is equal to 500 x 2 1000 nm for the second.
As a result, we can say that the difference for the nth maxima is 500n.
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