Respuesta :
The number of grams of Na used in the reaction is 0.414 g.
What is vapour pressure?
The tendency of a substance to transform into a gaseous or vapour state is measured by vapour pressure, which increases with temperature.
Given data:
Volume of gas, V = 246 mL = 0.246 L
Temperature, T = 25 degree C =298 K
Total pressure, PT = 1.0 atm
Pressure of water = 0.0313 atm
The vapor pressure of gas, P = PT- vapor pressure of water
=1.0 atm - 0.0313 atm
= 0.9687 atm
∴ Number of moles of gas,
n = PV / RT
= (0.9687 atm) (0.246 L) / (0.082 Latm/mol.K) (298K)
=0.238/
= 0.009 mol
According to the stoichiometric equation twomoles of Na(s) are required to produce one mole of hydrogengas
∴ Number of moles of Na(s) is required
= moles of gas * 2
= 0.009 mol *2
= 0.018 mol
Mass of Na(s) required
= moles * atomic mass ofNa
= 0.018 mol *23 g/mol
= 0.414 g
Therefore, the number of grams of Na used in the reaction is 0.414 g.
To learn more about vapour pressure from the given link.
https://brainly.com/question/2693029
#SPJ4
