what is the concentration (m) of 39.88 ml of an unknown naoh solution if it required of to neutralize? question 34 options: a) 1211 b) 2788 c) 0.7617 d) 1.313 e) 1.211

Respuesta :

The concentration (m) of 39.88 ml of an unknown naoh solution if it required of to neutralize Option C: 0.7617

The amount is stated. 59 .88 ml No, the HcL capacity is 46.8 ml. The modularity of HcL is set to zero point 65 and 92. Therefore, we must determine the modularity of Noh in order to be certain that the nuclearization formula, which is the polarity of anyways multiplied by the volume of anyhow, will equal the majority of Hcl multiplied by the volume of HcL.

From this point on, it equals modernity of HcL multiplied by volume of HcL divided by volume of any wage. We will now enter the values over here, which are 46.08 multiplied by 0.6592 divided by 39.88, and seconds zero 7617 Mueller. Hcl required of to neutralize 0.7617 that translates to among the options offered. The appropriate response will be option C.

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This is incomplete question complete question is :

What is the concentration (M) of 39 88 mL of an unknown NaOH solution if it required 46 08 mL of 0.6592 M HCI to neutralize?