The time is required for a 5.75 mg sample of 51cr to decay to 0.700 mg is 99.4 days
What is decay constant?
Decay constant k = ln(2) / half life
= ln(2) / 27.8
= 0.024933 day⁻¹
For first order decay:
ln(M / M₀) = -kt
where M is mass remaining at time t and M₀ is initial mass.
ln(0.700/5/75) = -0.024933 * t
Time, t = 99.4 days
Hence, time is required for a 5.75 mg sample of 51cr to decay to 0.700 mg is 99.4 days.
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