a 3.1-kg object falls vertically downward in a viscous medium at a constant speed of 2.5 m/s. how much work is done by the force the viscous medium exerts on the object as it falls 85 cm?

Respuesta :

The work is done by the force the viscous medium exerts on the object as it falls 85 cm is -26.35 joules.

   The mass of the object is m = 3.1kg

    The speed of fall is v = 2.5 m/s

    The depth of fall is d = 85cm

Now here given that the velocity is constant, then the work energy is zero.

So, work done by the potential energy of the object and that of the viscous liquid we have

      W = Wv + Wp

Where  Wv is work done by viscous liquid and

Wv is the work done by the object

           Wp = mgd

So  

      0  = Wv + mgd

 Wv = -mgd

substituting values

Wv = -3.1x10x85

Wv = 26.35 joules

To know more about the work done, click the below link

https://brainly.com/question/13662169?referrer=searchResults

#SPJ4