The percentage by mass of acetic acid is 5.14%
What is percentage by mass?
It is defined as ratio of mass of substance to the mass of all substance multiply by 100.It is way to express concentration.
CH3COOH+NaOH= CH3COONa+H2O
we have 1 mole of acid for 1mole of base
Now , C=n/V
C= 0.299M ( its M not m so correct question)
V= 24.5 mL
no of moles = 0.299moles/L × 0.0245 L = 0.00733 moles
for neutralization of 0.00733 moles of Noah require 0.00733 moles of CH3COOH
given mass of acetic acid = no. of moles × molar mass
0.00733×60g/mole = 0.4398g
% mass of acetic acid =[ 0.4398g/8.55g]×100
⇒ 5.14%
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