The mass of the iodine that can be obtained from the reaction is 79.5 Kg.
We know that we have to look at the stoichiometry of the reaction so as to be able to solve the question well. We know that to look at the stoichiometry, it is important that we should able to consider the mass - mass relationship between the compounds.
We have the reaction equation written out in the form; [tex]2KI --- > 2K + I_{2}[/tex]. We have been told in the question as we can see above that a sample of potassium iodide are decomposed into the constituent elements. and the sample produced 24.4 kg of potassium.
Number of moles of the potassium produced = the sample produced 24.4 * 10^3 g/39 g/mol
= 625.6 moles
If the reaction produces 2 moles of potassium and 1 mole of iodine then the number of moles of iodine produced = 625.6 moles/2
= 312.8 moles
Mass of the iodine produced = 312.8 moles * 254 g/mol
= 79.5 Kg
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