Respuesta :
the energy of a photon that is emitted as a hydrogen atom makes a transition between the n is 13.6(n^2 - 1)/n^2 eV
From the hydrogen atom's first excited state to its ground state, an electron transitions.
the given part is
n1 = 1 and n2 = n
The energy of photon released,
E=13.6(1/n1^2 – 1/n2^2) eV
= 13.6(1/1^2 – 1/n^2) eV
= 13.6(n^2 - 1)/n^2 eV
The following hypotheses form the foundation of Bohr's model:
• He hypothesized that an atom's electron can move within a specified stable, circular orbits around the nucleus without producing radiation.
• Bohr discovered that the electron's angular momentum is quantized in size.
To know more about the hydrogen atom's first excited state, click the below link
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