Respuesta :
The number of grams of Na used in the reaction is 0.44grams.
Which is mass?
The amount of matter in an object is measured by its mass. The sum of an object's atoms, their density, and the types that make up those atoms together make up its mass.
Given information,
Molar mass = 22.99
2Na + 2H₂O ⟶ 2NaOH + H₂
P total = 1atm
PH₂O = 0.0313atm
T = 25°C
V = 246ml
The ideal gas law can be used to determine the moles of hydrogen,
pV = nRT
Determine the hydrogen partial pressure.
P total = PH₂+PH₂O
1 = PH₂ + 0.0313
PH₂ = 0.9687atm.
Calculate the volume in litres,
V = 246 mL = 0.246 L
Change the degree to kelvins,
T = (25.0 + 273.15) K = 298.15 K
Determine the hydrogen moles,
0.9687×0.246 = n × 0.08206×298.15
n = 0.2383/24.47
n = 0.009740 mol.
Moles of Na,
There is a 2 mol molar ratio. 1 mol Na: H2
Moles of Na = 0.009740 moles of H₂ × 2mol of Na/1 mol H₂
Moles of Na = 0.01948 mol.
Mass of Na = 0.01948 moles of Na × 22.99g of Na/1 mol of H₂
Mass of Na = 0.44grams.
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Complete question is " A piece of sodium metal reacts completely with water as follows: 2Na(s) + 2H2O(l) ⟶ 2NaOH(aq) + H2(g) The hydrogen gas generated is collected over water at 25.0°C. The volume of the gas is 246 mL measured at 1.00 atm. Calculate the number of grams of sodium used in the reaction. (Vapor pressure of water at 25°C = 0.0313 atm)".
