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an object with a mass m slides down a rough 37e inclined plane where the coefficient of kinetic friction is 0.20. what is the acceleration of the object?

Respuesta :

The acceleration of the object is 9.307 m / s when the object of mass (m) slides down an inclined plane and the coefficient of kinetic friction is given.

What is the Coefficient of Kinetic friction?

The resistive force of friction (Fr), which pushes the items together, is divided by the normal or perpendicular force (N), which pushes them apart, to produce the coefficient of friction (fr), which is a numerical value. The following formula represents it: fr = Fr/N.

Calculations:

angle θ = 37°

the coefficient of kinetic friction μ =  0.20

accleration a = g sin θ - μ g cos θ

                  = 5.897 - 1.5653

                  = 4.331 m / s²

(b).  length L = 10 m

initial velocity u = 0

the speed at the bottom of the plane is v

then from the relation v² - u² = 2aL

                               v = √[ 2aL ]

                                 = 9.307 m / s.

Hence, the acceleration of the object is 9.307 m / s.

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