The appropriate number of significant figures for the calculation of 7.5 + 2.26 + 1.311 + 2 is equivalent to 10.
Significant figures:
Any non-zero number is significant. The number 33.2 has 3 significant digits because all digits present are non-zero.
Zeros between two non-zero numbers are valid. 2051 has 4 significant digits. Zero is between 2 and 5.
For numbers in exponential notation:
N x 10x, all numbers spanning N are valid. "10" and "x" are not important. 5.02 x 10^4 has 3 significant digits.
"5.02." "10" and "4" are not important.
Provides the ability to change the precision of a value by manipulating its shape. For example, write 1100 with 3 significant digits. 1100 has 2 significant digits. The trailing two zeros are not significant. Adding a decimal at the end brings the number to the 1100th significant digit (according to rule 5).
We can create a 3-significant digit of 1.10 x 10^3.
In the question of adding all we get,
7.5 + 2.26 = 9.76
9.76 + 1.311 + 2
9.76 + 1.311 = 11.071
11.071 + 2
11.071 + 2 = 13.071
13.071
Round 13.071 → 13
This is because the total sum of the numbers gives a value of 13.071.
However, the number '2' has only one significant figure.
Therefore, we need to restrict our solution to one significant figure.
Therefore, on rounding off the solution becomes '10' with only one significant figure.
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