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what is the net torque on the wheel due to these three forces for an axis perpendicular to the wheel and passing through its center? let counterclockwise torques be positive.

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The magnitude of the net torque on the wheel due to these three forces for an axis perpendicular to the wheel and passing through its center is

¹/₂MR³a.

What would be the Net torque on the wheel?

The net torque on the wheel is determined from the moment of inertia of the pulley and the angular acceleration.

∑τ = Iα

where;

  • I is moment of inertia
  • α is angular acceleration

the moment of inertia of the axis perpendicular to the wheel and passing through its center is calculated as;

  • I = ¹/₂MR²
  • τ = ¹/₂MR²α
  • τ = ¹/₂MR²(aR)
  • τ = ¹/₂MR³a

where;

a is the acceleration due to the applied force.

Thus, the magnitude of the net torque on the wheel due to these three forces for an axis perpendicular to the wheel and passing through its center is ¹/₂MR³a.

To know more about net torque , visit:

https://brainly.com/question/29806735

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