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find the second smallest positive integer that gives a remainder of $2$ when divided by $3$ and gives a remainder of $3$ when divided by $7$.

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rafikiedu08

The second-smallest positive integer that, when divided by 3, leaves a remainder of 2, and when divided by 7, leaves a remainder of 3 is 38

Given that,

We have to find the second-smallest positive number that, when divided by 3, leaves a remainder of 2, and when divided by 7, leaves a remainder of 3.

We know that,

We get equations as

N = 3a + 2

N = 7b + 3

Subtracting these equations we have that

3a - 7b - 1  = 0

3a - 7b =  1

So,

a=12 and b=5

The second integer we get is 38

Therefore, the second-smallest positive number that, when divided by 3, leaves a remainder of 2, and when divided by 7, leaves a remainder of 3 is 38

To learn more about integer visit: https://brainly.com/question/15276410

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