Potential difference would the charged particles have to be accelerated to aquire the velocity of [tex]v[/tex] is [tex]{\frac{mv^{2} }{2q} }[/tex].
The effort required to move a unit charge from one location to another in an electric field is known as the electrical potential difference. In other words, the electric potential difference between the two charged bodies is the definition of the potential difference.
The two bodies are said to have a potential difference when one of them is charged to a different electric potential than the other charged body. Both bodies are exerting maximum effort while under stress and tension.Volts are used to measure potential difference.
Since kinetic energy = [tex]\frac{mv^{2}} {2}[/tex]
Potential energy = qV
This kinetic energy is achieved by application of outside potential difference
Hence qV = [tex]\frac{mv^{2}} {2}[/tex]
Thus V = [tex]{\frac{mv^{2} }{2q} }[/tex]
To know more about potential difference refer:
https://brainly.com/question/23716417
#SPJ4