the number of milliters of 0.540 m ba(oh)2 required is 97.80 ml
The given equation of reaction is
NiBr2(aq) + Ba(OH)2(aq) --> Ni(OH)2(s)+BaBr2(aq)
molarity of NiBr2 is 0.531 M
volume = 166 ml
Molarity of Ba(OH)2 = 0.54 M
let volume is V liters
According to the equation ,
1mole of NiBr2 requires --> 1moles of Ba(OH)2
0.531 * 0.166 = V * .540
v =[tex]\frac{0.531*0.166}{0.54}[/tex]
V = 97.80 ml
Molarity (also called molarity, bulk concentration, or substance concentration) is a measure of the concentration of a chemical species.
To find the molarity of a solution, divide the number of moles of solute by the total volume of the solution in liters.
Learn more about molarity here : https://brainly.com/question/26873446
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