The concentration of the diluted solution will be 0.13 M
It asks you to find the concentration, which is the safe to assume that the unit is Molarity (M). Also, the unit was used in the problem as well.
Molarity has the units of moles/L so we have to work on getting to this point.
The problem states that you have the 2.29 mL of a 6.00 M concentration. First, we will need moles. To get the moles, we use stoichiometry,
2.29 mL = 0.00229 L
0.00229 L x ( 6 moles/ L) = 0.01374 moles
0.00229 L x ( 6 moles/ L) = 0.01374 moles
This is how many moles are present inside the solution.
To find the new concentration, we divide the total number of moles by the new volume in the Liters:
0.01374 moles/0.100L = 0.1374 M
Rounding to two significant figures, we get 0.13 M.
To know more about molarity, please refer:
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