The coordinates of S(x₁, y₁)=(3/2 , 5) if F(0, 2) and G(2,6) and the lines divided in the ratio 1:3
Finding the ratio by which a line segment is divided by a point internally or externally in coordinate geometry is done using the Section formula. The centroid, incenter, and ex center of a triangle are determined using it. Finding systems' centers of mass, equilibrium locations, etc. are all done using this method in physics. Finding the ratio by which a line segment is divided by a point internally or externally in coordinate geometry is done using the Section formula. The centroid, incenter, and ex center of a triangle are determined using it.
Given,
F(0, 2) and G(2, 6)
And also given that the points S lies on the way along FG then:
The lines divides the ratio,
1:3= m:n
Here we have to find the coordinates of S, we get:
S(x₁, y₁)=((mx₁+n x₂)/(m+ n), (my₁+n y₂)/(m+ n))
=((1(0)+3(2))/4 , (1(2)+3(6))/4)
=(6/4 , 20/4)
=(3/2 , 5)
S(x₁, y₁)=(3/2 , 5)
Therefore, the coordinates of S(x₁, y₁)=(3/2 , 5).
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