The annual percentage rate of the investment account is of:
14.1%.
The amount of money earned, in compound interest, after t years, is given by:
[tex]A(t) = P\left(1 + \frac{r}{n}\right)^{nt}[/tex]
In which:
The effective annual interest rate is given as follows:
[tex]E = \left(1 + \frac{r}{n}\right)^n[/tex]
In this problem we have a semi-annual compounding, hence:
n = 2.
The effective rate was of 14.6%, hence E = 1.146, and thus the interest rate is obtained as follows:
[tex]E = \left(1 + \frac{r}{n}\right)^n[/tex]
[tex]1.146 = \left(1 + \frac{r}{2}\right)^2[/tex]
1 + 0.5r = 1.0705 (applying to square root to both sides).
0.5r = 0.0705
r = 0.0705/0.5
r = 0.141 = 14.1%.
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