if 30.7 grams of bromine trifluoride react to form 17.9 grams of bromine, 10.32g of fluorine must be formed simultaneously.
In chemistry for the calculation of large amounts of very small quantities such as atoms or molecules or other objects generally we use mole chemistry.
2BrF3 + Br2 → Br2+3F2
1mole Br2 formed = 3 mole F2 formed
159.80g Br2 formed = 3 × 30.7 g F2 formed
than 17.9 g Br2 formed = 3×30.7×17.9/ 159.80 g of F2
10.32 g of F2 is formed
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