Respuesta :
Mass of 23592u must undergo fission to operate a 1000-mw power plant for one day if the conversion efficiency is 31 % is (92)^(235)U`
For 1000MW ouptput , the total power generation is 3000MW, of which 2000W=MW is rejected as "waste" heat. Thus the total energy released in year (3×107s) from fission is about (3×109)(3×107)≈1017 If each fission releases 200MeV of energy, the number of fission required is
(10172×108(1.6×10−19)≈3≈1027fissions The mass of a single uranium atom is about (235u)(1.66×10−27kg/u)≈4.5×10−25kg, so that mass needed is (1017)(2×108)(1.6×10−19) approxeapproxfissionorabouta→n.Since._(92)^(235)U` is only a fraction of normal uranium, and even when requiremnet for uranium is of the order of tens of tons.
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