how long will it take to deposit 0.00235 moles of gold by the electrolysis of kaucl4(aq) using a current of 0.214 amperes?

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Time taken  to deposit 0.00235 moles of gold by the electrolysis of kaucl4(aq) using a current of 0.214 amperes is  53.0 min

Note that the oxidation number of gold is +3 in the aqueous solution given. We can then determine how many moles of e- are needed.

The most common oxidation states of gold are +1 and +3. This implies it gives either 1 or 3 electrons to form stable mixtures. For instance, in AuCl3 , chloride particles have a - 1 oxidation state so gold will have Au + 3(- 1) = 0, so gold will have a +3 oxidation state.

The oxidation number or oxidation state of any atom is the capacity of that atom to gain or lose electrons. The oxidation state is the charge on an atom when it is in its ionic form, or when in a molecule. The charge is negative when an atom tends to take electrons or the atom is more electronegative, while the charge is positive when an atom has a capacity to give electrons.

As the oxidation state is determined as particles, so the oxidation state of any neutral molecule is zero. So any molecule without a charge has a 0 oxidation number. Then by adding the individual oxidation numbers we can take out the oxidation number of any component to be positive or negative.

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