The molarity of sodium hydroxide is 0.192 M
This is a acid-base titration between a strong acid and a strong base, therefore, this reaction is completely done, and the reaction is the following:
NaOH + HCl -------> NaCl + H2O
Assuming a 1:1 mole ratio, the following is true:
1 mole NaOH = 1 mole HCl
Expressing in concentration and volume:
Mb * Vb = Ma * Va
We have the concentration and volume of the acid, and the volume of the base, so we can solve for the concentration:
Mb* 28.84 = 0.2215*25
Mb = [tex]\frac{0.2215*25}{28.84}[/tex]
Mb = 0.192 M
This is the concentration of the NaOH solution
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