Answer:
1st answer is correct
Step-by-step explanation:
[tex]\sf \frac{1}{2} +\frac{2b}{3}[/tex]
Given that,
b = -5
To find the value of the above expression, replace b with -5.
[tex]\sf \frac{1}{2} +\frac{2b}{3}\\\\\sf \frac{1}{2} +\frac{2*(-5)}{3}\\\\\sf \frac{1}{2} +\frac{-10}{3}[/tex]
Now, to solve the above fractions, you have to make the denominator the same.
For that, multiply both the numerator and denominator of (1/2) & (-10/3) by 3 & 2 respectively.
Let us solve it now.
[tex]\sf \frac{1}{2} +\frac{-10}{3}\\\\\sf \frac{1}{2} -\frac{10}{3}\\\\\sf \frac{1*3}{2*3} -\frac{10*2}{3*2}\\\\\sf\frac{3}{6} -\frac{20}{6} \\\\\sf\frac{-17}{6}[/tex]
