contestada

a discussion of digital ethics appears in an article. one question posed in the article is: what proportion of college students have used cell phones to cheat on an exam? suppose you have been asked to estimate this proportion for students enrolled at a large university. how many students should you include in your sample if you want to estimate this proportion to within 0.07 with 95% confidence? (round your answer up to the nearest whole number.)

Respuesta :

Number of students included  in the sample to estimate the proportion with confidence interval 95% is equal to 9604.

As given in the question,

Confidence interval = 95%

z -critical value for 95% confidence interval = 1.96

Estimate proportion is in the limit 0f 0.07

Let us assume value of

sample proportion 'p' = 0.5

Margin of error  = 0.01

level of significance = 0.05

let 'n' be the sample size to represent number of students included for the hypothesis.

n = p ( 1 - p ) ( z- critical value / margin of error )²

⇒ n = 0.5 ( 1 - 0.5 )( 1.96 / 0.01 )²

⇒ n = 0.5 (0.5 ) (3.8416/ 0.0001)

⇒ n = 0.25 × 38416

⇒ n = 9604

Therefore, the number of students included for the hypothesis to estimate the proportion with confidence interval 95% is equal to 9604.

learn more about confidence interval here

brainly.com/question/24131141

#SPJ4

Otras preguntas