The required probability that the duration will actually exceed 23 days is 22.66%.
A probability distribution is a factual capability that depicts every one of the potential qualities and probabilities for an irregular variable inside a given reach.
We have,
μ = 25, σ = 4,
For 90% confidence interval, Z = 1.645
Then,
Z =( x -μ )/σ =(x - 25)/4
1.645 = (x - 25)/4x
x = 4(1.645) + 25 = 31.58 days
when duration increase by 3 days
So, Z = 3/4 = 0.75
Probability = 22.66%
Thus, required probability is 22.66%.
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