Respuesta :
The partial pressure of a mixture of gases contains 0.310mol ch4, 0.270mol c2h6, and 0.300 c3h8 with total pressure 1.30atm are 0.476atm (for CH4), 0.390atm (for C2H6), 0.433atm (for C3H8).
What is partial pressure?
In a mixture of gases, each constituent gas has a partial pressure of that constituent gas as if it alone occupied the entire volume of the original mixture at the same temperature.
Now, let's calculate the partial pressure for each gas.
Given from the question
0.310 mol CH4
0.270 mol C2H6
0.300 mol C3H8
The total pressure is 1.30 atm
Partial pressure = mole fraction * total pressure
Total moles of gas = 0.310 + 0.270 + 0.300 = 0.88 moles
Partial pressure of CH4
= (CH4 mol / total moles) * total pressure
= (0.310 / 0.88) * 1.3
= 0.458atm (rounded)
Partial pressure of C2H6
= (C2H6 mol / total moles) * total pressure
= (0.270 / 0.88) * 1.3
= 0.399atm (rounded)
Partial pressure of C3H8
= (C3H8 mol / total moles) * total pressure
= (0.300 / 0.88) * 1.3
= 0.443atm (rounded)
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