An element of atomic number 88 decays radioactively to anelement of atomic number 82.Which of the following emissions achieve this result?a.one alpha particle and one beta particleb. three alpha particlesc. one alpha particled. six beta particles

Respuesta :

Three alpha particles are lost.

The process by which unstable nuclei emit radiation and lose energy  is called radioactive decay. If a material contains an unstable core, it is considered radioactive.

There are three basic types of radioactive decay, Decay of alpha, beta and gamma. Radioactivity can be measured by counting decays per second.

Explanation:

Six protons are lost when atomic number 88 decays to atomic number 82.

The following explains whether the radioactive decay process leads to the loss of six protons.

1. One Alpha and  one beta particles: Alpha particles have two protons and beta particles have one electron. So this is not a loss of 6 protons.

2. Three alpha particles: Alpha particles have two protons. So when 3 alpha particles decay, 6 protons are lost.

3. One Alpha particle: An alpha particle has two protons, so six protons are never lost.

4. Six Beta Particles: A beta particle has 1 electron, therefore 6 protons will be gained during the decay.

Therefore, three alpha particles is correct because when three of them are lost, six protons are lost.

Read more about radioactive decay at:

brainly.com/question/12641249

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